Integrand size = 20, antiderivative size = 158 \[ \int \frac {x^{10} \left (A+B x^2\right )}{\left (a+b x^2\right )^3} \, dx=\frac {2 a^2 (3 A b-5 a B) x}{b^6}-\frac {a (A b-2 a B) x^3}{b^5}+\frac {(A b-3 a B) x^5}{5 b^4}+\frac {B x^7}{7 b^3}-\frac {a^4 (A b-a B) x}{4 b^6 \left (a+b x^2\right )^2}+\frac {a^3 (17 A b-21 a B) x}{8 b^6 \left (a+b x^2\right )}-\frac {9 a^{5/2} (7 A b-11 a B) \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{8 b^{13/2}} \]
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Time = 0.20 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {466, 1828, 1824, 211} \[ \int \frac {x^{10} \left (A+B x^2\right )}{\left (a+b x^2\right )^3} \, dx=-\frac {9 a^{5/2} (7 A b-11 a B) \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{8 b^{13/2}}-\frac {a^4 x (A b-a B)}{4 b^6 \left (a+b x^2\right )^2}+\frac {a^3 x (17 A b-21 a B)}{8 b^6 \left (a+b x^2\right )}+\frac {2 a^2 x (3 A b-5 a B)}{b^6}-\frac {a x^3 (A b-2 a B)}{b^5}+\frac {x^5 (A b-3 a B)}{5 b^4}+\frac {B x^7}{7 b^3} \]
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Rule 211
Rule 466
Rule 1824
Rule 1828
Rubi steps \begin{align*} \text {integral}& = -\frac {a^4 (A b-a B) x}{4 b^6 \left (a+b x^2\right )^2}-\frac {\int \frac {-a^4 (A b-a B)+4 a^3 b (A b-a B) x^2-4 a^2 b^2 (A b-a B) x^4+4 a b^3 (A b-a B) x^6-4 b^4 (A b-a B) x^8-4 b^5 B x^{10}}{\left (a+b x^2\right )^2} \, dx}{4 b^6} \\ & = -\frac {a^4 (A b-a B) x}{4 b^6 \left (a+b x^2\right )^2}+\frac {a^3 (17 A b-21 a B) x}{8 b^6 \left (a+b x^2\right )}+\frac {\int \frac {-a^4 (15 A b-19 a B)+8 a^3 b (3 A b-4 a B) x^2-8 a^2 b^2 (2 A b-3 a B) x^4+8 a b^3 (A b-2 a B) x^6+8 a b^4 B x^8}{a+b x^2} \, dx}{8 a b^6} \\ & = -\frac {a^4 (A b-a B) x}{4 b^6 \left (a+b x^2\right )^2}+\frac {a^3 (17 A b-21 a B) x}{8 b^6 \left (a+b x^2\right )}+\frac {\int \left (16 a^3 (3 A b-5 a B)-24 a^2 b (A b-2 a B) x^2+8 a b^2 (A b-3 a B) x^4+8 a b^3 B x^6+\frac {9 \left (-7 a^4 A b+11 a^5 B\right )}{a+b x^2}\right ) \, dx}{8 a b^6} \\ & = \frac {2 a^2 (3 A b-5 a B) x}{b^6}-\frac {a (A b-2 a B) x^3}{b^5}+\frac {(A b-3 a B) x^5}{5 b^4}+\frac {B x^7}{7 b^3}-\frac {a^4 (A b-a B) x}{4 b^6 \left (a+b x^2\right )^2}+\frac {a^3 (17 A b-21 a B) x}{8 b^6 \left (a+b x^2\right )}-\frac {\left (9 a^3 (7 A b-11 a B)\right ) \int \frac {1}{a+b x^2} \, dx}{8 b^6} \\ & = \frac {2 a^2 (3 A b-5 a B) x}{b^6}-\frac {a (A b-2 a B) x^3}{b^5}+\frac {(A b-3 a B) x^5}{5 b^4}+\frac {B x^7}{7 b^3}-\frac {a^4 (A b-a B) x}{4 b^6 \left (a+b x^2\right )^2}+\frac {a^3 (17 A b-21 a B) x}{8 b^6 \left (a+b x^2\right )}-\frac {9 a^{5/2} (7 A b-11 a B) \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{8 b^{13/2}} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.00 \[ \int \frac {x^{10} \left (A+B x^2\right )}{\left (a+b x^2\right )^3} \, dx=-\frac {2 a^2 (-3 A b+5 a B) x}{b^6}+\frac {a (-A b+2 a B) x^3}{b^5}+\frac {(A b-3 a B) x^5}{5 b^4}+\frac {B x^7}{7 b^3}+\frac {a^4 (-A b+a B) x}{4 b^6 \left (a+b x^2\right )^2}+\frac {a^3 (17 A b-21 a B) x}{8 b^6 \left (a+b x^2\right )}+\frac {9 a^{5/2} (-7 A b+11 a B) \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{8 b^{13/2}} \]
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Time = 2.52 (sec) , antiderivative size = 144, normalized size of antiderivative = 0.91
method | result | size |
default | \(\frac {\frac {1}{7} b^{3} B \,x^{7}+\frac {1}{5} A \,b^{3} x^{5}-\frac {3}{5} B a \,b^{2} x^{5}-a A \,b^{2} x^{3}+2 B \,a^{2} b \,x^{3}+6 a^{2} A b x -10 a^{3} B x}{b^{6}}-\frac {a^{3} \left (\frac {\left (-\frac {17}{8} b^{2} A +\frac {21}{8} a b B \right ) x^{3}-\frac {a \left (15 A b -19 B a \right ) x}{8}}{\left (b \,x^{2}+a \right )^{2}}+\frac {9 \left (7 A b -11 B a \right ) \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{8 \sqrt {a b}}\right )}{b^{6}}\) | \(144\) |
risch | \(\frac {B \,x^{7}}{7 b^{3}}+\frac {A \,x^{5}}{5 b^{3}}-\frac {3 B a \,x^{5}}{5 b^{4}}-\frac {a A \,x^{3}}{b^{4}}+\frac {2 B \,a^{2} x^{3}}{b^{5}}+\frac {6 a^{2} A x}{b^{5}}-\frac {10 a^{3} B x}{b^{6}}+\frac {\left (\frac {17}{8} a^{3} b^{2} A -\frac {21}{8} a^{4} b B \right ) x^{3}+\frac {a^{4} \left (15 A b -19 B a \right ) x}{8}}{b^{6} \left (b \,x^{2}+a \right )^{2}}+\frac {63 \sqrt {-a b}\, a^{2} \ln \left (-\sqrt {-a b}\, x -a \right ) A}{16 b^{6}}-\frac {99 \sqrt {-a b}\, a^{3} \ln \left (-\sqrt {-a b}\, x -a \right ) B}{16 b^{7}}-\frac {63 \sqrt {-a b}\, a^{2} \ln \left (\sqrt {-a b}\, x -a \right ) A}{16 b^{6}}+\frac {99 \sqrt {-a b}\, a^{3} \ln \left (\sqrt {-a b}\, x -a \right ) B}{16 b^{7}}\) | \(236\) |
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Time = 0.32 (sec) , antiderivative size = 468, normalized size of antiderivative = 2.96 \[ \int \frac {x^{10} \left (A+B x^2\right )}{\left (a+b x^2\right )^3} \, dx=\left [\frac {80 \, B b^{5} x^{11} - 16 \, {\left (11 \, B a b^{4} - 7 \, A b^{5}\right )} x^{9} + 48 \, {\left (11 \, B a^{2} b^{3} - 7 \, A a b^{4}\right )} x^{7} - 336 \, {\left (11 \, B a^{3} b^{2} - 7 \, A a^{2} b^{3}\right )} x^{5} - 1050 \, {\left (11 \, B a^{4} b - 7 \, A a^{3} b^{2}\right )} x^{3} - 315 \, {\left (11 \, B a^{5} - 7 \, A a^{4} b + {\left (11 \, B a^{3} b^{2} - 7 \, A a^{2} b^{3}\right )} x^{4} + 2 \, {\left (11 \, B a^{4} b - 7 \, A a^{3} b^{2}\right )} x^{2}\right )} \sqrt {-\frac {a}{b}} \log \left (\frac {b x^{2} - 2 \, b x \sqrt {-\frac {a}{b}} - a}{b x^{2} + a}\right ) - 630 \, {\left (11 \, B a^{5} - 7 \, A a^{4} b\right )} x}{560 \, {\left (b^{8} x^{4} + 2 \, a b^{7} x^{2} + a^{2} b^{6}\right )}}, \frac {40 \, B b^{5} x^{11} - 8 \, {\left (11 \, B a b^{4} - 7 \, A b^{5}\right )} x^{9} + 24 \, {\left (11 \, B a^{2} b^{3} - 7 \, A a b^{4}\right )} x^{7} - 168 \, {\left (11 \, B a^{3} b^{2} - 7 \, A a^{2} b^{3}\right )} x^{5} - 525 \, {\left (11 \, B a^{4} b - 7 \, A a^{3} b^{2}\right )} x^{3} + 315 \, {\left (11 \, B a^{5} - 7 \, A a^{4} b + {\left (11 \, B a^{3} b^{2} - 7 \, A a^{2} b^{3}\right )} x^{4} + 2 \, {\left (11 \, B a^{4} b - 7 \, A a^{3} b^{2}\right )} x^{2}\right )} \sqrt {\frac {a}{b}} \arctan \left (\frac {b x \sqrt {\frac {a}{b}}}{a}\right ) - 315 \, {\left (11 \, B a^{5} - 7 \, A a^{4} b\right )} x}{280 \, {\left (b^{8} x^{4} + 2 \, a b^{7} x^{2} + a^{2} b^{6}\right )}}\right ] \]
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Time = 0.80 (sec) , antiderivative size = 280, normalized size of antiderivative = 1.77 \[ \int \frac {x^{10} \left (A+B x^2\right )}{\left (a+b x^2\right )^3} \, dx=\frac {B x^{7}}{7 b^{3}} + x^{5} \left (\frac {A}{5 b^{3}} - \frac {3 B a}{5 b^{4}}\right ) + x^{3} \left (- \frac {A a}{b^{4}} + \frac {2 B a^{2}}{b^{5}}\right ) + x \left (\frac {6 A a^{2}}{b^{5}} - \frac {10 B a^{3}}{b^{6}}\right ) - \frac {9 \sqrt {- \frac {a^{5}}{b^{13}}} \left (- 7 A b + 11 B a\right ) \log {\left (- \frac {9 b^{6} \sqrt {- \frac {a^{5}}{b^{13}}} \left (- 7 A b + 11 B a\right )}{- 63 A a^{2} b + 99 B a^{3}} + x \right )}}{16} + \frac {9 \sqrt {- \frac {a^{5}}{b^{13}}} \left (- 7 A b + 11 B a\right ) \log {\left (\frac {9 b^{6} \sqrt {- \frac {a^{5}}{b^{13}}} \left (- 7 A b + 11 B a\right )}{- 63 A a^{2} b + 99 B a^{3}} + x \right )}}{16} + \frac {x^{3} \cdot \left (17 A a^{3} b^{2} - 21 B a^{4} b\right ) + x \left (15 A a^{4} b - 19 B a^{5}\right )}{8 a^{2} b^{6} + 16 a b^{7} x^{2} + 8 b^{8} x^{4}} \]
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Time = 0.27 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.08 \[ \int \frac {x^{10} \left (A+B x^2\right )}{\left (a+b x^2\right )^3} \, dx=-\frac {{\left (21 \, B a^{4} b - 17 \, A a^{3} b^{2}\right )} x^{3} + {\left (19 \, B a^{5} - 15 \, A a^{4} b\right )} x}{8 \, {\left (b^{8} x^{4} + 2 \, a b^{7} x^{2} + a^{2} b^{6}\right )}} + \frac {9 \, {\left (11 \, B a^{4} - 7 \, A a^{3} b\right )} \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{8 \, \sqrt {a b} b^{6}} + \frac {5 \, B b^{3} x^{7} - 7 \, {\left (3 \, B a b^{2} - A b^{3}\right )} x^{5} + 35 \, {\left (2 \, B a^{2} b - A a b^{2}\right )} x^{3} - 70 \, {\left (5 \, B a^{3} - 3 \, A a^{2} b\right )} x}{35 \, b^{6}} \]
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Time = 0.27 (sec) , antiderivative size = 162, normalized size of antiderivative = 1.03 \[ \int \frac {x^{10} \left (A+B x^2\right )}{\left (a+b x^2\right )^3} \, dx=\frac {9 \, {\left (11 \, B a^{4} - 7 \, A a^{3} b\right )} \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{8 \, \sqrt {a b} b^{6}} - \frac {21 \, B a^{4} b x^{3} - 17 \, A a^{3} b^{2} x^{3} + 19 \, B a^{5} x - 15 \, A a^{4} b x}{8 \, {\left (b x^{2} + a\right )}^{2} b^{6}} + \frac {5 \, B b^{18} x^{7} - 21 \, B a b^{17} x^{5} + 7 \, A b^{18} x^{5} + 70 \, B a^{2} b^{16} x^{3} - 35 \, A a b^{17} x^{3} - 350 \, B a^{3} b^{15} x + 210 \, A a^{2} b^{16} x}{35 \, b^{21}} \]
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Time = 4.95 (sec) , antiderivative size = 246, normalized size of antiderivative = 1.56 \[ \int \frac {x^{10} \left (A+B x^2\right )}{\left (a+b x^2\right )^3} \, dx=x^5\,\left (\frac {A}{5\,b^3}-\frac {3\,B\,a}{5\,b^4}\right )-\frac {x\,\left (\frac {19\,B\,a^5}{8}-\frac {15\,A\,a^4\,b}{8}\right )-x^3\,\left (\frac {17\,A\,a^3\,b^2}{8}-\frac {21\,B\,a^4\,b}{8}\right )}{a^2\,b^6+2\,a\,b^7\,x^2+b^8\,x^4}-x^3\,\left (\frac {a\,\left (\frac {A}{b^3}-\frac {3\,B\,a}{b^4}\right )}{b}+\frac {B\,a^2}{b^5}\right )-x\,\left (\frac {B\,a^3}{b^6}-\frac {3\,a\,\left (\frac {3\,a\,\left (\frac {A}{b^3}-\frac {3\,B\,a}{b^4}\right )}{b}+\frac {3\,B\,a^2}{b^5}\right )}{b}+\frac {3\,a^2\,\left (\frac {A}{b^3}-\frac {3\,B\,a}{b^4}\right )}{b^2}\right )+\frac {B\,x^7}{7\,b^3}+\frac {9\,a^{5/2}\,\mathrm {atan}\left (\frac {a^{5/2}\,\sqrt {b}\,x\,\left (7\,A\,b-11\,B\,a\right )}{11\,B\,a^4-7\,A\,a^3\,b}\right )\,\left (7\,A\,b-11\,B\,a\right )}{8\,b^{13/2}} \]
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